952=2x^2+16x+336

Solution for 952=2x^2+16x+336 equation:

952=2x^2+16x+336

We move all terms to the left:

952-(2x^2+16x+336)=0

We get rid of parentheses

-2x^2-16x-336+952=0

We add all the numbers together, and all the variables

-2x^2-16x+616=0

a = -2; b = -16; c = +616;
Δ = b2-4ac
Δ = -162-4·(-2)·616
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-72}{2*-2}=\frac{-56}{-4}
=+14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+72}{2*-2}=\frac{88}{-4}
=-22
$